01. Point on Rectangle Border . Къде греша?Благодаря!

egencheva 0 Точки

01. Point on Rectangle Border . Къде греша?Благодаря!

import java.util.Scanner;

public class PointOnBorder {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        //x1, y1, x2, y2, x и y (като се гарантира, че x1 < x2 и y1 < y2).
        double x1 = Double.parseDouble(scanner.nextLine());
        double y1 = Double.parseDouble(scanner.nextLine());
        double x2 = Double.parseDouble(scanner.nextLine());
        double y2 = Double.parseDouble(scanner.nextLine());
        double x = Double.parseDouble(scanner.nextLine());
        double y = Double.parseDouble(scanner.nextLine());

        boolean xBorderIsValid = (x == x1) || (x == x2);
        boolean yBorderIsValid = (y == y1) || (y == y2);

        if (xBorderIsValid) {
            if (y > y1 && y < y2) ;
            System.out.println("Border");
        } else if (yBorderIsValid) {
            if (x > x1 && x < x2) ;
            System.out.println("Border");
        } else {
            System.out.println("Inside / Outside");
        }
    }
}

Тагове:

03/10/2018 18:58:02 Programming Basics with Java

Виж всички отговори

Tanasis 39 Точки

Здрасти, може би така ще ти проработи

package Complicated;

import java.util.Scanner;

public class ExactPointInRectangle {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        double x1 = Double.parseDouble(scanner.nextLine());
        double y1 = Double.parseDouble(scanner.nextLine());
        double x2 = Double.parseDouble(scanner.nextLine());
        double y2 = Double.parseDouble(scanner.nextLine());
        double x = Double.parseDouble(scanner.nextLine());
        double y = Double.parseDouble(scanner.nextLine());

        boolean isOnLeftSide = (x == x1 && y >= y1 && y <= y2);
        boolean isOnRightSide = (x == x2 && y >= y1 && y <= y2);
        boolean isOnTopSide = (y == y1 && x >= x1 && x <= x2);
        boolean isOnBottomSide = (y == y2 && x >= x1 && x <= x2);
        if (isOnBottomSide || isOnLeftSide || isOnRightSide || isOnTopSide) {
            System.out.println("Border");
        } else {
            System.out.println("Inside / Outside");
        }
    }
}

03/10/2018 20:04:33

ValenNEW 51 Точки

03/10/2018 20:33:55 04/10/2018 01:50:05

egencheva 0 Точки

Благодаря :)

08/10/2018 12:57:02

egencheva 0 Точки

Благодаря!

Така разписано разбирам къде е бил проблема! Страхотно!

08/10/2018 13:12:23

Виж всички отговори