Защо Judge ми дава 0/100 на задача 02.Pascal or camel case?

LilianaVelvheva 17 Точки

Защо Judge ми дава 0/100 на задача 02.Pascal or camel case?

Това е моето решение: https://pastebin.com/mqGFH2vx

Ето условието на задачата:

2.Pascal or Camel Case

An HTML file is given and your task is to write a function that takes two string parameters as an input and transforms the first parameter to the type required by the second parameter.

The first parameter will be the text that you need to modify depending on the second parameter. The words in it will always be separated by space.
The second parameter will be either "Camel Case" or "Pascal Case". In case of different input, your output should be "Error!"

When the button is clicked the function should convert the first string to either of the cases. The output should consist of only one word - the string you have modified. Once your output is done, you should set it as HTML to the <span> element. For more information, see the examples below:

Example

Input	Output
"this is an example", "Camel Case"	thisIsAnExample
"secOND eXamPLE", "Pascal Case"	SecondExample
"Invalid Input", "Another Case"	Error!

Тагове:

03/10/2021 19:13:12 JavaScript Advanced

Виж всички отговори

Axiomatik 2422 Точки

function solve() {
  const text = document.getElementById("text").value;
  const naming = document.getElementById("naming-convention").value;
  const resultContainer = document.getElementById("result");

  const splitted = text.split(" ");

  // resultString must be assigned with let, otherwise can not be modified
  let resultString = "";

  if (naming == "Pascal Case") {
    for (let i = 0; i < splitted.length; i++) {
      resultString += splitted[i][0].toUpperCase() +
        splitted[i].slice(1, splitted[i].length).toLowerCase();
    }
    // resultContainer must receive final value
    resultContainer.textContent = resultString;
  } else if (naming == "Camel Case") {
    resultString += splitted[0][0].toLowerCase()
      + splitted[0].slice(1, splitted[0].length).toLowerCase();
    for (let i = 1; i < splitted.length; i++) {
      resultString += splitted[i][0].toUpperCase() +
        splitted[i].slice(1, splitted[i].length).toLowerCase();
    }
    // resultContainer must receive final value
    resultContainer.textContent = resultString;
  } else {
    // resultContainer.textContent() = resultString;
    resultContainer.textContent = "Error!";
  }
}

03/10/2021 21:02:46

LilianaVelvheva 17 Точки

Много благодаря.

04/10/2021 10:36:36

Виж всички отговори