Задача No.10-Fill-The-Box от упражнението за функции - Python Advanced Jan 2022

Здравейте колеги, става въпрос за задача №10-Fill-The-Box от упражнението за функции. Лекторът предложи решение, което минава в Judge със 100/100 (https://pastebin.com/mPgtbH2N), но остана нерешен казусът, когато подаваме елемент, който е равен на обема, но алгоритъмът престава да чете оставащите елементи. Например, с решениeто предложено по време на упражненинето при вход "print(fill_the_box(10, 10, 10, 1000, "Finish", 2, 15, 30))" бихме получили като изход "No more free space! You have 0 more cubes.", което не е правилният отговор, защото имаме оставащи 47 елемента. Тоест правилният отговор трябва да бъде "No more free space! You have 47 more cubes." Явно от Софтуни не са предвидили такъв тест. Някой от вас успя ли да намери работещо решение и за този случай? Условието на задачата е както следва:

1. *Fill the Box

Write a function called fill_the_box that receives a different number of arguments representing:

the height
the length of a box
the width of a box
n-times a different number of cubes with exact size 1 x 1 x 1
a string "Finish"

Your task is to fill the box with the given cubes until the current argument equals "Finish".

Note: Submit only the function in the judge system

Input

There will be no input. Just parameters passed to your function.

Output

The function should return a string in the following format:

If, at the end, there is free space left in the box, print:
- "There is free space in the box. You could put {free space in cubes} more cubes."

If there is no free space in the box, print:

"No more free space! You have {cubes left} more cubes.

Examples

Test Code	Output	Comment
print(fill_the_box(2, 8, 2, 2, 1, 7, 3, 1, 5, "Finish"))	There is free space in the box. You could put 13 more cubes.	The size of the box: 2 * 8 * 2 = 32 We put the cubes consistently. At the end there is more free space left.
print(fill_the_box(5, 5, 2, 40, 11, 7, 3, 1, 5, "Finish"))	No more free space! You have 17 more cubes.	The size of the box: 5 * 5 * 2 = 50 We put the cubes consistently. First, we put 40 cubes and there is free space left. Then we try to put 11 cubes, but there is only space for 10. Cubes left: 1 + 7 + 3 + 1 + 5 = 17
print(fill_the_box(10, 10, 10, 40, "Finish", 2, 15, 30))	There is free space in the box. You could put 960 more cubes.

def fill_the_box(height, length, width, *args): volume = height * length * width cubes_left = 0 is_finish = False for x in args: if x == 'Finish': is_finish = True elif is_finish: cubes_left += x elif x > volume: x -= volume cubes_left += x volume = 0 else: volume -= x if volume > 0: return f"There is free space in the box. You could put {volume} more cubes." else: return f"No more free space! You have {cubes_left} more cubes." print(fill_the_box(10, 10, 10, 1000, "Finish", 2, 15, 30)) # No more free space! You have 47 more cubes.

def fill_the_box(height, length, width, *args): volume = height * length * width cubes = sum(x for x in args if x != 'Finish') for el in args: if el == 'Finish': break if el > volume: difference = el - volume volume -= (el - difference) cubes -= (el - difference) else: volume -= el cubes -= el if volume: return f"There is free space in the box. You could put {volume} more cubes." else: return f"No more free space! You have {cubes} more cubes." print(fill_the_box(10, 10, 10, 1000, "Finish", 2, 15, 30))