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Във форума е въведено ограничение, което позволява на потребителите единствено да разглеждат публикуваните въпроси.

bozhidar_kapudzhiev avatar bozhidar_kapudzhiev 0 Точки

Сортиране на ArrayList

нов  съм  и  не  ми ясно  как  се създава  сортиране  .  Трябва да  създам  сортировака в  определен  диапазон  , опитах  се да създам  нов  клас  и да  му  задам  параметри  но  не  се  получи  .Някой  може  ли  да  помогне

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0
Programming Basics
nickwork avatar nickwork 657 Точки

Дай това което си написал да го погледнем (аз или някой др от форума) и ще ти покажем как става.

0
bozhidar_kapudzhiev avatar bozhidar_kapudzhiev 0 Точки
import java.util.Random;
import java.util.Scanner;
import java.util.*;


public class RangeControl {
    public static void main(String[] args) {

        for (int i = 0; i < 1; i++) {
            System.out.println(getRandomNumberInRange(1, 5000));
        }

    }


    private static int getRandomNumberInRange(int min, int max) {

        if (min >= max) {
            throw new IllegalArgumentException("max must be greater than min");
        }

        Random r = new Random();
        return r.nextInt((max - min) + 1) + min;


    }


    public static class CyclicShiftApp extends RangeControl {

        public static void main(String[] args) {
            Scanner scan = new Scanner(System.in);
            ArrayList<Integer> empployee= new ArrayList<>();
            while (scan.hasNextInt()) {
                empployee.add(scan.nextInt());

            }
        }
    }
}

 

 

 

import java.io.Serializable;
import java.util.stream.Collectors;

public class Employee implements Comparable<Employee_Users> {


    private  Object Employee_Users;
    private int id = 1;
    public String fname=null;
    public String lname=null ;
    public String dataOfResgeter;
    public int shoping=1;
    public float total=1;
    public String stars=null;

    public Employee(int id, String fname, String lname,String dataOfResgeter, int shopping,float total ) {
        this.id = id;
        this.fname = fname;
        this.lname = lname;
        this.dataOfResgeter = dataOfResgeter;
        this.shoping = shopping;
        this.total = total;

        if (total<99) this.stars="*";
        else if (total<299) this.stars="**";
        else if (total<499) this.stars="***";
        else if (total<999) this.stars="****";
        else this.stars="*****";

        }

    public Employee() {

    }


    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getFname() {
        return fname;
    }

    public void setFname(String fname) {
        this.fname = fname;
    }

    public String getLname() {
        return lname;
    }

    public void setLname(String lname) {
        this.lname = lname;
    }


    public String getDataOfResgeter() {
        return dataOfResgeter;
    }

    public void setDataOfResgeter(String dataOfResgeter) {
        this.dataOfResgeter = dataOfResgeter;
    }

    public int getShoping() {
        return shoping;
    }

    public void setShoping(int shoping) {
        this.shoping = shoping;
    }

    public float getTotal() {
        return total;
    }

    public void setTotal(float total) {
        this.total = total;
    }





    /**
     * Compares this object with the specified object for order.  Returns a
     * negative integer, zero, or a positive integer as this object is less
     * than, equal to, or greater than the specified object.
     *
     * <p>The implementor must ensure
     * {@code sgn(x.compareTo(y)) == -sgn(y.compareTo(x))}
     * for all {@code x} and {@code y}.  (This
     * implies that {@code x.compareTo(y)} must throw an exception iff
     * {@code y.compareTo(x)} throws an exception.)
     *
     * <p>The implementor must also ensure that the relation is transitive:
     * {@code (x.compareTo(y) > 0 && y.compareTo(z) > 0)} implies
     * {@code x.compareTo(z) > 0}.
     *
     * <p>Finally, the implementor must ensure that {@code x.compareTo(y)==0}
     * implies that {@code sgn(x.compareTo(z)) == sgn(y.compareTo(z))}, for
     * all {@code z}.
     *
     * <p>It is strongly recommended, but <i>not</i> strictly required that
     * {@code (x.compareTo(y)==0) == (x.equals(y))}.  Generally speaking, any
     * class that implements the {@code Comparable} interface and violates
     * this condition should clearly indicate this fact.  The recommended
     * language is "Note: this class has a natural ordering that is
     * inconsistent with equals."
     *
     * <p>In the foregoing description, the notation
     * {@code sgn(}<i>expression</i>{@code )} designates the mathematical
     * <i>signum</i> function, which is defined to return one of {@code -1},
     * {@code 0}, or {@code 1} according to whether the value of
     * <i>expression</i> is negative, zero, or positive, respectively.
     *
     * @return a negative integer, zero, or a positive integer as this object
     * is less than, equal to, or greater than the specified object.
     * @throws NullPointerException if the specified object is null
     * @throws ClassCastException   if the specified object's type prevents it
     *                              from being compared to this object.
     */
    @Override
    public String toString() {
        return fname +" "+lname+",  "+shoping+",  "+total+",  "+dataOfResgeter+" "+stars+"\n";
    }

    /**
     * Compares this object with the specified object for order.  Returns a
     * negative integer, zero, or a positive integer as this object is less
     * than, equal to, or greater than the specified object.
     *
     * <p>The implementor must ensure
     * {@code sgn(x.compareTo(y)) == -sgn(y.compareTo(x))}
     * for all {@code x} and {@code y}.  (This
     * implies that {@code x.compareTo(y)} must throw an exception iff
     * {@code y.compareTo(x)} throws an exception.)
     *
     * <p>The implementor must also ensure that the relation is transitive:
     * {@code (x.compareTo(y) > 0 && y.compareTo(z) > 0)} implies
     * {@code x.compareTo(z) > 0}.
     *
     * <p>Finally, the implementor must ensure that {@code x.compareTo(y)==0}
     * implies that {@code sgn(x.compareTo(z)) == sgn(y.compareTo(z))}, for
     * all {@code z}.
     *
     * <p>It is strongly recommended, but <i>not</i> strictly required that
     * {@code (x.compareTo(y)==0) == (x.equals(y))}.  Generally speaking, any
     * class that implements the {@code Comparable} interface and violates
     * this condition should clearly indicate this fact.  The recommended
     * language is "Note: this class has a natural ordering that is
     * inconsistent with equals."
     *
     * <p>In the foregoing description, the notation
     * {@code sgn(}<i>expression</i>{@code )} designates the mathematical
     * <i>signum</i> function, which is defined to return one of {@code -1},
     * {@code 0}, or {@code 1} according to whether the value of
     * <i>expression</i> is negative, zero, or positive, respectively.
     *
     * @param o the object to be compared.
     * @return a negative integer, zero, or a positive integer as this object
     * is less than, equal to, or greater than the specified object.
     * @throws NullPointerException if the specified object is null
     * @throws ClassCastException   if the specified object's type prevents it
     *                              from being compared to this object.
     */
    @Override
    public int compareTo(Employee_Users o) {
        return this.id-o.getId();
    }

    /**
     * Compares this object with the specified object for order.  Returns a
     * negative integer, zero, or a positive integer as this object is less
     * than, equal to, or greater than the specified object.
     *
     * <p>The implementor must ensure
     * {@code sgn(x.compareTo(y)) == -sgn(y.compareTo(x))}
     * for all {@code x} and {@code y}.  (This
     * implies that {@code x.compareTo(y)} must throw an exception iff
     * {@code y.compareTo(x)} throws an exception.)
     *
     * <p>The implementor must also ensure that the relation is transitive:
     * {@code (x.compareTo(y) > 0 && y.compareTo(z) > 0)} implies
     * {@code x.compareTo(z) > 0}.
     *
     * <p>Finally, the implementor must ensure that {@code x.compareTo(y)==0}
     * implies that {@code sgn(x.compareTo(z)) == sgn(y.compareTo(z))}, for
     * all {@code z}.
     *
     * <p>It is strongly recommended, but <i>not</i> strictly required that
     * {@code (x.compareTo(y)==0) == (x.equals(y))}.  Generally speaking, any
     * class that implements the {@code Comparable} interface and violates
     * this condition should clearly indicate this fact.  The recommended
     * language is "Note: this class has a natural ordering that is
     * inconsistent with equals."
     *
     * <p>In the foregoing description, the notation
     * {@code sgn(}<i>expression</i>{@code )} designates the mathematical
     * <i>signum</i> function, which is defined to return one of {@code -1},
     * {@code 0}, or {@code 1} according to whether the value of
     * <i>expression</i> is negative, zero, or positive, respectively.
     *
     * @param o the object to be compared.
     * @return a negative integer, zero, or a positive integer as this object
     * is less than, equal to, or greater than the specified object.
     * @throws NullPointerException if the specified object is null
     * @throws ClassCastException   if the specified object's type prevents it
     *                              from being compared to this object.
     */

    }







import javax.security.auth.Subject;
import javax.swing.*;
import java.awt.*;
import java.nio.FloatBuffer;
import java.util.*;
import java.util.List;
import java.util.stream.Collector;
import java.util.stream.Collectors;
import java.util.stream.IntStream;

public class Employee_Users extends Employee {


    public Employee_Users(int id, String fname, String lname, String dataOfResgeter, int shopping, float total) {
        super(id, fname, lname, dataOfResgeter, shopping, total);
    }


    public static <IndexSorter> void main(String[] args) {
        List<Employee> employees = new ArrayList<Employee>();
        Employee e1 = new Employee(101, "Ivan", "Ivanov", "12.02.2019", 4, 150);
        Employee e2 = new Employee(102, "Georgi", "Stoyanov", "17.07.2018", 4, 256);
        Employee e3 = new Employee(103, "Nikoleta", "Dimitrova", "05.04.2017", 6, 320);
        Employee e4 = new Employee(104, "Dayana", "Petrova", "11.05.2019", 2, 40);
        Employee e5 = new Employee(105, "Petiya ", "Ogniyanova", "20.06.2016", 30, 1600);
        Employee e6 = new Employee(106, "Adreyana", "Andreeva", "15.10.2015", 50, 3000);
        Employee e7 = new Employee(107, "Ivaiyo", "Petkov", "14.10.2017 ", 50, 2585);
        Employee e8 = new Employee(108, "Jivko", "Qnkov", "30.03.2017", 16, 4500);
        Employee e9 = new Employee(109, "Desilava", "Yordanova", "6.12.2014", 70, 3500);
        Employee e10 = new Employee(110, "Krasimira", "Evtimova", "18.01.2013", 40, 5990);
        Employee e11 = new Employee(111, "Gergana", "Ivanova", "12.05.2016", 15, 750);
        Employee e12 = new Employee(112, "Boris", "Kolev", "05.06.2017", 18, 453);
        Employee e13 = new Employee(113, "Nikolay", "Draganov", "01.09.2019", 2, 50);
        Employee e14 = new Employee(114, "Milen", "Filipov", "30.08.2018", 6, 360);
        Employee e15 = new Employee(115, "Jivka", "Kisiova", "04.12.2017", 60, 3798);
        Employee e16 = new Employee(116, "Ivan", "Hristov", "19.11.2016", 5, 120);
        Employee e17 = new Employee(117, "Atansa", "Kirov", "05.07.2018", 7, 456);
        Employee e18 = new Employee(118, "Marin", "Kolev", "07.09.2014", 10, 260);
        Employee e19 = new Employee(119, "Kiril", "Lazarov", "20.12.2018", 74, 2453);
        Employee e20 = new Employee(120, "Liliya", "Kovacheva", "04.03.2019", 9, 80);


        employees.add(e1);
        employees.add(e2);
        employees.add(e3);
        employees.add(e4);
        employees.add(e5);
        employees.add(e6);
        employees.add(e7);
        employees.add(e8);
        employees.add(e9);
        employees.add(e10);
        employees.add(e11);
        employees.add(e12);
        employees.add(e13);
        employees.add(e14);
        employees.add(e15);
        employees.add(e16);
        employees.add(e17);
        employees.add(e18);
        employees.add(e19);
        employees.add(e20);

        Collections.sort(employees, new FirstNameSort(employees, new LastNameSorter()));
        System.out.println(employees);

        employees.sort((Comparator.comparing(Employee::getTotal)));

        System.out.print(employees);

    }

    }




import java.util.Comparator;
import java.util.List;

public class FirstNameSort implements Comparator<Employee> {


    public FirstNameSort(List<Employee> employees, LastNameSorter lastNameSorter) {

    }

    /**
     * Compares its two arguments for order.  Returns a negative integer,
     * zero, or a positive integer as the first argument is less than, equal
     * to, or greater than the second.<p>
     * <p>
     * The implementor must ensure that {@code sgn(compare(x, y)) ==
     * -sgn(compare(y, x))} for all {@code x} and {@code y}.  (This
     * implies that {@code compare(x, y)} must throw an exception if and only
     * if {@code compare(y, x)} throws an exception.)<p>
     * <p>
     * The implementor must also ensure that the relation is transitive:
     * {@code ((compare(x, y)>0) && (compare(y, z)>0))} implies
     * {@code compare(x, z)>0}.<p>
     * <p>
     * Finally, the implementor must ensure that {@code compare(x, y)==0}
     * implies that {@code sgn(compare(x, z))==sgn(compare(y, z))} for all
     * {@code z}.<p>
     * <p>
     * It is generally the case, but <i>not</i> strictly required that
     * {@code (compare(x, y)==0) == (x.equals(y))}.  Generally speaking,
     * any comparator that violates this condition should clearly indicate
     * this fact.  The recommended language is "Note: this comparator
     * imposes orderings that are inconsistent with equals."<p>
     * <p>
     * In the foregoing description, the notation
     * {@code sgn(}<i>expression</i>{@code )} designates the mathematical
     * <i>signum</i> function, which is defined to return one of {@code -1},
     * {@code 0}, or {@code 1} according to whether the value of
     * <i>expression</i> is negative, zero, or positive, respectively.
     *
     * @param o1 the first object to be compared.
     * @param o2 the second object to be compared.
     * @return a negative integer, zero, or a positive integer as the
     * first argument is less than, equal to, or greater than the
     * second.
     * @throws NullPointerException if an argument is null and this
     *                              comparator does not permit null arguments
     * @throws ClassCastException   if the arguments' types prevent them from
     *                              being compared by this comparator.
     */
    @Override
    public int compare(Employee o1, Employee o2) {
        return o1.getFname().compareTo(o2.getFname());
    }
}

import java.util.Comparator;

public class LastNameSorter  implements Comparator<Employee>{

    /**
     * Compares its two arguments for order.  Returns a negative integer,
     * zero, or a positive integer as the first argument is less than, equal
     * to, or greater than the second.<p>
     * <p>
     * The implementor must ensure that {@code sgn(compare(x, y)) ==
     * -sgn(compare(y, x))} for all {@code x} and {@code y}.  (This
     * implies that {@code compare(x, y)} must throw an exception if and only
     * if {@code compare(y, x)} throws an exception.)<p>
     * <p>
     * The implementor must also ensure that the relation is transitive:
     * {@code ((compare(x, y)>0) && (compare(y, z)>0))} implies
     * {@code compare(x, z)>0}.<p>
     * <p>
     * Finally, the implementor must ensure that {@code compare(x, y)==0}
     * implies that {@code sgn(compare(x, z))==sgn(compare(y, z))} for all
     * {@code z}.<p>
     * <p>
     * It is generally the case, but <i>not</i> strictly required that
     * {@code (compare(x, y)==0) == (x.equals(y))}.  Generally speaking,
     * any comparator that violates this condition should clearly indicate
     * this fact.  The recommended language is "Note: this comparator
     * imposes orderings that are inconsistent with equals."<p>
     * <p>
     * In the foregoing description, the notation
     * {@code sgn(}<i>expression</i>{@code )} designates the mathematical
     * <i>signum</i> function, which is defined to return one of {@code -1},
     * {@code 0}, or {@code 1} according to whether the value of
     * <i>expression</i> is negative, zero, or positive, respectively.
     *
     * @param o1 the first object to be compared.
     * @param o2 the second object to be compared.
     * @return a negative integer, zero, or a positive integer as the
     * first argument is less than, equal to, or greater than the
     * second.
     * @throws NullPointerException if an argument is null and this
     *                              comparator does not permit null arguments
     * @throws ClassCastException   if the arguments' types prevent them from
     *                              being compared by this comparator.
     */
    @Override

    public int compare(Employee o1, Employee o2) {
        return o1.getLname().compareTo(o2.getLname());
    }
}

 

Резултат от това  което съм направил:

"C:\Program Files\Java\jdk-13.0.1\bin\java.exe" "-javaagent:C:\Program Files\JetBrains\IntelliJ IDEA Community Edition 2019.3\lib\idea_rt.jar=49988:C:\Program Files\JetBrains\IntelliJ IDEA Community Edition 2019.3\bin" -Dfile.encoding=UTF-8 -classpath "C:\Users\Bozhidar Kapudzhiev\AppData\Local\Temp\Proj-8\out\production\Proj-8" Employee_Users
[Adreyana Andreeva,  50,  3000.0,  15.10.2015 *****
, Atansa Kirov,  7,  456.0,  05.07.2018 ***
, Boris Kolev,  18,  453.0,  05.06.2017 ***
, Dayana Petrova,  2,  40.0,  11.05.2019 *
, Desilava Yordanova,  70,  3500.0,  6.12.2014 *****
, Georgi Stoyanov,  4,  256.0,  17.07.2018 **
, Gergana Ivanova,  15,  750.0,  12.05.2016 ****
, Ivaiyo Petkov,  50,  2585.0,  14.10.2017  *****
, Ivan Ivanov,  4,  150.0,  12.02.2019 **
, Ivan Hristov,  5,  120.0,  19.11.2016 **
, Jivka Kisiova,  60,  3798.0,  04.12.2017 *****
, Jivko Qnkov,  16,  4500.0,  30.03.2017 *****
, Kiril Lazarov,  74,  2453.0,  20.12.2018 *****
, Krasimira Evtimova,  40,  5990.0,  18.01.2013 *****
, Liliya Kovacheva,  9,  80.0,  04.03.2019 *
, Marin Kolev,  10,  260.0,  07.09.2014 **
, Milen Filipov,  6,  360.0,  30.08.2018 ***
, Nikolay Draganov,  2,  50.0,  01.09.2019 *
, Nikoleta Dimitrova,  6,  320.0,  05.04.2017 ***
, Petiya  Ogniyanova,  30,  1600.0,  20.06.2016 *****
]
[Dayana Petrova,  2,  40.0,  11.05.2019 *
, Nikolay Draganov,  2,  50.0,  01.09.2019 *
, Liliya Kovacheva,  9,  80.0,  04.03.2019 *
, Ivan Hristov,  5,  120.0,  19.11.2016 **
, Ivan Ivanov,  4,  150.0,  12.02.2019 **
, Georgi Stoyanov,  4,  256.0,  17.07.2018 **
, Marin Kolev,  10,  260.0,  07.09.2014 **
, Nikoleta Dimitrova,  6,  320.0,  05.04.2017 ***
, Milen Filipov,  6,  360.0,  30.08.2018 ***
, Boris Kolev,  18,  453.0,  05.06.2017 ***
, Atansa Kirov,  7,  456.0,  05.07.2018 ***
, Gergana Ivanova,  15,  750.0,  12.05.2016 ****
, Petiya  Ogniyanova,  30,  1600.0,  20.06.2016 *****
, Kiril Lazarov,  74,  2453.0,  20.12.2018 *****
, Ivaiyo Petkov,  50,  2585.0,  14.10.2017  *****
, Adreyana Andreeva,  50,  3000.0,  15.10.2015 *****
, Desilava Yordanova,  70,  3500.0,  6.12.2014 *****
, Jivka Kisiova,  60,  3798.0,  04.12.2017 *****
, Jivko Qnkov,  16,  4500.0,  30.03.2017 *****
, Krasimira Evtimova,  40,  5990.0,  18.01.2013 *****
]
Process finished with exit code 0
 

 

 

 

 

0
12/03/2020 09:58:25
bozhidar_kapudzhiev avatar bozhidar_kapudzhiev 0 Точки

Трябва  да изведа  списък  със  рейтиг две (**)

0
Можем ли да използваме бисквитки?
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Назад
Функционални
Използваме бисквитки и подобни технологии, за да предоставим нашите услуги. Използваме „сесийни“ бисквитки, за да Ви идентифицираме временно. Те се пазят само по време на активната употреба на услугите ни. След излизане от приложението, затваряне на браузъра или мобилното устройство, данните се трият. Използваме бисквитки, за да предоставим опцията „Запомни Ме“, която Ви позволява да използвате нашите услуги без да предоставяте потребителско име и парола. Допълнително е възможно да използваме бисквитки за да съхраняваме различни малки настройки, като избор на езика, позиции на менюта и персонализирано съдържание. Използваме бисквитки и за измерване на маркетинговите ни усилия.
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