Josephus Permutation
Здравейте колеги, някой дали е решил задачата да бутне едно рамо?
Условие:
You are now to create a program that prints a Josephus permutation, receiving two lines of code (the list itself (string with elements separated by a single space) and a number k) as if they were in a circle and counted out every k places until none remained.
Моето решение което дава 60/100, а пък резултатите са ми верни
circle = input().split(' ') kill_count = int(input()) result = [] circle_int = [] counter = 0 # making str circle into int for i in circle: circle_int.append(int(i)) while len(circle_int) >= 1: # adding killed man to result list for i in circle_int: counter += 1 if counter % kill_count == 0: result.append(i) # removing killed man from the circle for i in result: if i in circle_int: circle_int.remove(i) print(str(result).replace(' ', ''))
Благодаря !