03. House Party

gina78 4 Точки

03. House Party

Здравейте, как се решава тая задача?някой може ли да помогни,

1.House Party

Write a program that keeps track of a guests that are going to a house party. On the first input line you are going to receive how many commands you are going to have. On the next lines you are going to receive some of the following inputs:

"{name} is going!"

"{name} is not going!"

If you receive the first type of input, you have to add the person if he/she is not in the list (If he/she is in the list print on the console: "{name} is already in the list!"). If you receive the second type of input, you have to remove the person if he/she is in the list (if not print: "{name} is not in the list!"). At the end print each guest on a new line.

Examples

Input

Output

Allie is going!

George is going!

John is not going!

George is not going!

John is not in the list!

Allie

Tom is going!

Annie is going!

Tom is going!

Garry is going!

Jerry is going!

Tom is already in the list!

Tom

Annie

Garry

Jerry

Тагове:

22/06/2019 12:43:32 PHP Fundamentals 22/06/2019 12:44:07

Виж всички отговори

willystyle 2472 Точки

<?php
$count = intval(readline());
$list = [];
for ($i=0; $i < $count; $i++) {
    $command = readline();
    $name = explode(' ', $command)[0];
    if (strpos($command, 'is going!') !== false) {
        if (in_array($name, $list)) {
            echo "{$name} is already in the list!" . PHP_EOL;
        } else {
            $list[] = $name;
        }
    } else if (strpos($command, 'is not going!') !== false) {
        if (!in_array($name, $list)) {
            echo "{$name} is not in the list!" . PHP_EOL;
        } else {
            $index = array_search($name, $list);
            unset($list[$index]);
        }
    }
}
echo implode(PHP_EOL, $list);

22/06/2019 15:58:28

gina78 4 Точки

благодаря

23/06/2019 15:41:49

gina78 4 Точки

04.Array Advanced Operations

Shift right 1

Shift left 2

в тая задача всичко но това не мога да направя незнам как, можеш ли да ми помогнеш?благодаря

23/06/2019 15:43:59

willystyle 2472 Точки

Сигурно мога, но дай кода до където си стигнала, не ми се пише цялата задача от нула.

23/06/2019 16:25:32

gina78 4 Точки

<?php

$arr = explode(" ", readline());
while (true) {
$input = explode(" ", readline());
$comand = $input[0];
switch ($comand) {
case "Add":
$arr [] = $element;
break;
case "Insert":
//Insert {number} {index} - insert number at given index
$indexArr = $input[2];
$number = $input[1];
if ($indexArr >= 0 && $indexArr <= count($arr)) {
array_splice($arr, $indexArr, 0, $number);
}
break;
case "Remove":
$indexArr = $input[1];
if (in_array($indexArr, $arr)) {
array_splice($arr, $indexArr, 1);
} else {
echo "Invalid index" . PHP_EOL;
}
break;
case "Shift":
if ($input[1] === "left") {
$shiftIndex = $input[2];
if (!in_array($shiftIndex, $arr)) {
//array_splice($arr, $index, 0,$index);
}
}
break;
default :
//
}

if ($comand == "End") {
break;
}
}
//print_r($arr);
echo implode(" ",$arr);

23/06/2019 17:31:43

willystyle 2472 Точки

рефактор, ако нещо не е ясно питай:

<?php
$arr = explode(" ", readline());
while (true) {
    $input = explode(" ", readline());
    $comand = $input[0];
    if ($comand == "End") {
        break;
    }
    switch ($comand) {
        case "Add":
            $element = $input[1];
            $arr[] = $element;
            break;
        case "Insert":
            //Insert {number} {index} - insert number at given index
            $indexArr = $input[2];
            $number = $input[1];
            if ($indexArr >= 0 && $indexArr < count($arr)) {
                array_splice($arr, $indexArr, 0, $number);
            } else {
                echo "Invalid index" . PHP_EOL;
            }
            break;
        case "Remove":
            $indexArr = $input[1];
            if ($indexArr >= 0 && $indexArr < count($arr)) {
                array_splice($arr, $indexArr, 1);
            } else {
                echo "Invalid index" . PHP_EOL;
            }
            break;
        case "Shift":
            $count = $input[2];
            if ($input[1] === "left") {
                for ($i=0; $i < $count; $i++) {
                    $first = array_shift($arr);
                    $arr[] = $first;
                }
            } elseif ($input[1] === "right") {
                for ($i=0; $i < $count; $i++) {
                    $last = array_pop($arr);
                    array_splice($arr, 0, 0, $last);
                }
            }
            break;
        default:
            //
    }
}
//print_r($arr);
echo implode(" ", $arr);

23/06/2019 17:57:02 23/06/2019 18:01:25

gina78 4 Точки

Благодаря

23/06/2019 18:10:15

Виж всички отговори