06. Summation Pairs

Здравейте колеги, на тази задача не можах да рабера какво точно се очва от мен или греша в решението. Някой може ли да ми даде насоки?

1.Summation Pairs

On the first line, you will receive a string of numbers separated by space. On the second line, you'll receive a target number. Your task is to find all pairs of numbers whose sum equals the target number.

For each found pair print "{number} + {number} = {target_number}".

Then, save only the unique pairs. Note: (1, 2) and (2, 1) are unique.

Also, you should keep track of how many iterations you've done.

At the end print all the iterations done in format: "Iterations done: {total_number_of_iterations}".

On the following lines, print the unique pairs in the format: "(first_number, second_number)".

The order in which we print the result does not matter.

Examples

Input

Output

1 5 4 2 2 3 1 3 2

1 + 3 = 4

2 + 2 = 4

3 + 1 = 4

1 + 3 = 4

Iterations done: 36

(3, 1)

(1, 3)

(2, 2)

11 8 5 6 9 2 9 7 3 4

8 + 3 = 11

5 + 6 = 11

9 + 2 = 11

2 + 9 = 11

7 + 4 = 11

Iterations done: 45

(7, 4)

(9, 2)

(2, 9)

(8, 3)

(5, 6)

Моя код с решението е този. Но не ми илизат добре изходите

https://pastebin.com/0umF9RmP

numbers = [int(x) for x in input().split()] target_number = int(input()) unique_pairs = set() iterations = 0 for i in range(0, len(numbers)): for j in range(i + 1, len(numbers)): a = numbers[i] b = numbers[j] if a + b == target_number: unique_pairs.add((a, b)) print(f'{a} + {b} = {target_number}') iterations += 1 print(f'Iterations done: {iterations}') for pair in unique_pairs: print(pair)