JS Essentials Exam 6 august 2019 Find the Special Subsequence

DenitsaPambelova 3 Точки

JS Essentials Exam 6 august 2019 Find the Special Subsequence

Здравейте,колеги!

Някой може ли да сподели решение на 2 задача от този изпит. Ето условието:

Problem 2. Find the Special Subsequence
Your task is to find the longest special subsequence in the given array.
The special subsequence is a sequence, which contains negative-positive-negative or positive-negative-positive numbers in that order. If there are 2 special sequences with equal length get the first one.
Input
An array - contains the given numbers from the sequence.
Output
If there is no special subsequence print: "In {sequence} no special sequence is found"
Otherwise show each of the elements in that sequence separated with comma and single space (", ")
"The longest sequence is {sequence}"
Note:
0 (zero) is neither positive nor negative number, so it always breaks the sequence
Examples
Input    Output Comment
[1, -2, 1, -1, 2, 1, -1]   The longest sequence is 1, -2, 1, -1, 2   There are 2 special subsequences. The first contains 5 numbers, the second containes 2 numbers, so we print the length of the first one.
[-1, -1, -1, 1, -1]   The longest sequence is -1, 1, -1
[1, 2, 3, 4, 5]   In 1, 2, 3, 4, 5 no special sequence is found

Тагове:

12/08/2019 16:12:56 JavaScript Fundamentals

willystyle 2472 Точки

Best Answer

Пробвай това, за съжаление джъдж още не отворен за тест:

function solve(arr) {
    let longestSubsequence = [];
    for (let i = 0; i < arr.length - 1; i++) {
        let currentSubsequence = [];
        currentSubsequence.push(arr[i]);
        currentIndex = i;
        while (true) {
            currentIndex++;
            if ((arr[currentIndex - 1] > 0 && arr[currentIndex] < 0) || (arr[currentIndex - 1] < 0 && arr[currentIndex] > 0)) {
                currentSubsequence.push(arr[currentIndex]);
            } else {
                i = currentIndex;
                break;
            }
        }
        if (currentSubsequence.length > longestSubsequence.length) {
            longestSubsequence = currentSubsequence.slice();
        }
    }
    if (longestSubsequence.length >= 3) {
        console.log(`The longest sequence is ${longestSubsequence.join(', ')}`);
    } else {
        console.log(`In ${arr.join(', ')} no special sequence is found`);
    }
}

solve([1, -2, 1, -1, 2, 1, -1]);
solve([-1, -1, -1, 1, -1]);
solve([1, 2, 3, 4, 5]);

12/08/2019 20:48:39

DenitsaPambelova 3 Точки

Благодаря!

13/08/2019 14:57:21

Todorov_Stanimir 1 Точки

Заповядайте, моето решение https://pastebin.com/crCQGzaK.

Тествано е в judge и дава максималния брой точки.

29/08/2019 19:20:50 29/08/2019 19:21:43

TeodorStefanovPld 1274 Точки

e какво толкова, 1 for цикъл от ляво надясно и проверяваш ако отговая на условието увеличаваш count-a ако запомняш колко е дълга и кой е индекса и продължаваш отново от 0. с 1 цикъл и 2 променливи за начало и дължина ще се реши.

12/08/2019 16:54:16

Във форума е въведено ограничение, което позволява на потребителите единствено да разглеждат публикуваните въпроси.

JS Essentials Exam 6 august 2019 Find the Special Subsequence