Loading...

Във форума е въведено ограничение, което позволява на потребителите единствено да разглеждат публикуваните въпроси.

PreslavaJeleva avatar PreslavaJeleva 8 Точки

Man-O-War - JS Mid Exam

Здравейте!

Опитвам се да реша задачата Man-O-War.

https://pastebin.com/g6NugqCR - в judge получавам 80/100.

Може ли някой да ми каже къде е грешката?

Благодаря!

Условието:

 

Problem 3 - Man-O-War

Problem for exam preparation for the Programming Fundamentals Course @SoftUni.

Submit your solutions in the SoftUni judge system at https://judge.softuni.org/Contests/Practice/Index/1773#2.

 

The pirates encounter a huge Man-O-War at sea.

Create a program that tracks the battle and either chooses a winner or prints a stalemate. On the first line, you will receive the status of the pirate ship, which is a string representing integer sections separated by ">". On the second line, you will receive the same type of status, but for the warship:

"{section1}>{section2}>{section3}… {sectionn}"

On the third line, you will receive the maximum health capacity a section of the ship can reach.

The following lines represent commands until "Retire":

  • "Fire {index} {damage}" - the pirate ship attacks the warship with the given damage at that section. Check if the index is valid and if not, skip the command. If the section breaks (health <= 0) the warship sinks, print the following and stop the program: "You won! The enemy ship has sunken."
  • "Defend {startIndex} {endIndex} {damage}" - the warship attacks the pirate ship with the given damage at that range (indexes are inclusive). Check if both indexes are valid and if not, skip the command. If the section breaks (health <= 0) the pirate ship sinks, print the following and stop the program:

"You lost! The pirate ship has sunken."

  • "Repair {index} {health}" - the crew repairs a section of the pirate ship with the given health. Check if the index is valid and if not, skip the command. The health of the section cannot exceed the maximum health capacity.
  • "Status" - prints the count of all sections of the pirate ship that need repair soon, which are all sections that are lower than 20% of the maximum health capacity. Print the following:

"{count} sections need repair."

In the end, if a stalemate occurs, print the status of both ships, which is the sum of their individual sections, in the following format:

"Pirate ship status: {pirateShipSum}

Warship status: {warshipSum}"

Input

  • On the 1st line, you are going to receive the status of the pirate ship (integers separated by '>')
  • On the 2nd line, you are going to receive the status of the warship
  • On the 3rd line, you will receive the maximum health a section of a ship can reach.
  • On the following lines, until "Retire", you will be receiving commands.

Output

  • Print the output in the format described above.

Constraints

  • The section numbers will be integers in the range [1….1000]
  • The indexes will be integers [-200….200]
  • The damage will be an integer in the range [1….1000]
  • The health will be an integer in the range [1….1000]

Examples

Input

Output

12>13>11>20>66

12>22>33>44>55>32>18

70

Fire 2 11

Fire 8 100

Defend 3 6 11

Defend 0 3 5

Repair 1 33

Status

Retire

2 sections need repair.

Pirate ship status: 135

Warship status: 205

Comments

First, we receive the command "Fire 2 11", and damage the warship at section index 2, which is currently 33, and after reduction, the status of the warship is the following:

12 22 22 44 55 32 18

The second and third commands have invalid indexes, so we skip them.

The fourth command, "Defend 0 3 5" damages 4 sections of the pirate ship with 5, which results in the following states:

7 8 6 15 66

The fifth command, "Repair 1 33" repairs the pirate ship section and adds 33 health to the current 8, which results in 41

Only 2 sections of the pirate ship (7 and 6) need repair soon.

In the end, there is a stalemate, so we print both ship statuses (sum of all sections).

 

Input

Output

2>3>4>5>2

6>7>8>9>10>11

20

Status

Fire 2 3

Defend 0 4 11

Repair 3 18

Retire

3 sections need repair.

You lost! The pirate ship has sunken.

     

JS Examples

Input

Output

(["12>13>11>20>66",

"12>22>33>44>55>32>18",

"70",

"Fire 2 11",

"Fire 8 100",

"Defend 3 6 11",

"Defend 0 3 5",

"Repair 1 33",

"Status",

"Retire"])

2 sections need repair.

Pirate ship status: 135

Warship status: 205

Comments

First, we receive the command "Fire 2 11", and damage the warship at section index 2, which is currently 33, and after reduction, the status of the warship is the following:

12 22 22 44 55 32 18

The second and third commands have invalid indexes, so we skip them.

The fourth command, "Defend 0 3 5" damages 4 sections of the pirate ship with 5, which results in the following states:

7 8 6 15 66

The fifth command, "Repair 1 33" repairs the pirate ship section and adds 33 health to the current 8, which results in 41

Only 2 sections of the pirate ship (7 and 6) need repair soon.

In the end, there is a stalemate, so we print both ship statuses (sum of all sections).

 

Input

Output

(["2>3>4>5>2",

"6>7>8>9>10>11",

"20",

"Status",

"Fire 2 3",

"Defend 0 4 11",

"Repair 3 18",

"Retire"])

3 sections need repair.

You lost! The pirate ship has sunken.

 

Тагове:
1
JavaScript Fundamentals
MartinBG avatar MartinBG 4803 Точки
Best Answer

Може да има има проблем, ако се подаде повече от веднъж командата "Status", заради дефинирането и инициализирането на тази променлива (ред №7) извън тялото на цикъла:

let counter = 0; //declared and initialized once, never reset
while(arr[0] !== "Retire"){
//...
}

Преместете я на ред №42 и решението ще мине:

    }else if(commands[0] === "Status"){
        let counter = 0; //declaration and initialization closer to the place where it is used
        for(let i = 0; i < pirateShip.length; i++){
            if(pirateShip[i] < maximumHealth * 0.2){
                counter++
            }
        }
        console.log(`${counter} sections need repair.`)
    }

 

1
PreslavaJeleva avatar PreslavaJeleva 8 Точки

Благодаря!! :) 

1
Catchy_Title avatar Catchy_Title 2 Точки

Todos os bons momentos do dia em que você ainda está acordado. Eu recomendaria comprar levitra generico pelo preço para que você nunca tenha o problema da impotência masculina. E eu vou te dizer - este é o melhor remédio que você precisa hoje.

0
Можем ли да използваме бисквитки?
Ние използваме бисквитки и подобни технологии, за да предоставим нашите услуги. Можете да се съгласите с всички или част от тях.
Назад
Функционални
Използваме бисквитки и подобни технологии, за да предоставим нашите услуги. Използваме „сесийни“ бисквитки, за да Ви идентифицираме временно. Те се пазят само по време на активната употреба на услугите ни. След излизане от приложението, затваряне на браузъра или мобилното устройство, данните се трият. Използваме бисквитки, за да предоставим опцията „Запомни Ме“, която Ви позволява да използвате нашите услуги без да предоставяте потребителско име и парола. Допълнително е възможно да използваме бисквитки за да съхраняваме различни малки настройки, като избор на езика, позиции на менюта и персонализирано съдържание. Използваме бисквитки и за измерване на маркетинговите ни усилия.
Рекламни
Използваме бисквитки, за да измерваме маркетинг ефективността ни, броене на посещения, както и за проследяването дали дадено електронно писмо е било отворено.